PHP 腳本顯示錯誤

我正在嘗試為 php-mysql 伺服器和 android 設備之間的數據交換編寫 Web 服務。但是服務顯示一些錯誤並且無法正常工作。

這是我的程式碼

<?php

    include 'config.inc.php';

    // Check whether username or password is set from android  
    if(isset($_POST['username']) && isset($_POST['password']))
    {
         // Innitialize Variable
         $result='';
         $username = $_POST['username'];
         $password = $_POST['password'];

         // Query database for row exist or not
         $sql = 'SELECT * FROM tbl_login WHERE  email = :username AND password = :password';
         $stmt = $conn->prepare($sql);
         $stmt->bindParam(':username', $username, PDO::PARAM_STR);
         $stmt->bindParam(':password', $password, PDO::PARAM_STR);
         $stmt->execute();
         if($stmt->rowCount())
         {
            $result="true";    
         }  
         elseif(!$stmt->rowCount())
         {
               $result="false";
         }

         // send result back to android
         echo $result;
   }

?>

現在我的同事是一名 android 開發人員，正在從 android 端製作登錄會話模組，他需要 Web 服務進行註冊和登錄。

你能解決錯誤嗎？或者

您能否為這些服務提供一些程式碼或連結到合適的資源？

您是否正確包含配置文件？是否獲得正確的數據庫連接？仔細檢查這些東西一次。

您的來源 coed 看起來不錯，但如果您在瀏覽器中得到任何錯誤，請提供您的錯誤。

你也可以試試下面的程式碼

<?php

  if($_SERVER['REQUEST_METHOD']=='POST'){
 // echo $_SERVER["DOCUMENT_ROOT"];  // /home1/demonuts/public_html
//including the database connection file
      include_once("config.php");

       $username = $_POST['username'];
   $password = $_POST['password'];

    if( $username == '' || $password == '' ){
           echo json_encode(array( "status" => "false","message" => "Parameter missing!") );
    }else{
       $query= "SELECT * FROM registerDemo WHERE username='$username' AND password='$password'";
           $result= mysqli_query($con, $query);

           if(mysqli_num_rows($result) > 0){  
            $query= "SELECT * FROM registerDemo WHERE username='$username' AND password='$password'";
                        $result= mysqli_query($con, $query);
                    $emparray = array();
                        if(mysqli_num_rows($result) > 0){  
                        while ($row = mysqli_fetch_assoc($result)) {
                                    $emparray[] = $row;
                                  }
                        }
              echo json_encode(array( "status" => "true","message" => "Login successfully!", "data" => $emparray) );
           }else{ 
               echo json_encode(array( "status" => "false","message" => "Invalid username or password!") );
           }
            mysqli_close($con);
    }
   } else{
           echo json_encode(array( "status" => "false","message" => "Error occured, please try again!") );
   }
?> 

如果您想獲得工作服務，請訪問php login 並在 android教程中註冊以獲取更多詳細資訊。

登記服務

<?php

  if($_SERVER['REQUEST_METHOD']=='POST'){
 // echo $_SERVER["DOCUMENT_ROOT"];  // /home1/demonuts/public_html
//including the database connection file
      include_once("config.php");

       $name = $_POST['name'];
   $username = $_POST['username'];
   $password = $_POST['password'];
   $hobby= $_POST['hobby'];

    if($name == '' || $username == '' || $password == '' || $hobby == ''){
           echo json_encode(array( "status" => "false","message" => "Parameter missing!") );
    }else{

           $query= "SELECT * FROM registerDemo WHERE username='$username'";
           $result= mysqli_query($con, $query);

           if(mysqli_num_rows($result) > 0){  
              echo json_encode(array( "status" => "false","message" => "Username already exist!") );
           }else{ 
            $query = "INSERT INTO registerDemo (name,hobby,username,password) VALUES ('$name','$hobby','$username','$password')";
            if(mysqli_query($con,$query)){

                $query= "SELECT * FROM registerDemo WHERE username='$username'";
                        $result= mysqli_query($con, $query);
                    $emparray = array();
                        if(mysqli_num_rows($result) > 0){  
                        while ($row = mysqli_fetch_assoc($result)) {
                                    $emparray[] = $row;
                                  }
                        }
               echo json_encode(array( "status" => "true","message" => "Successfully registered!" , "data" => $emparray) );
            }else{
                echo json_encode(array( "status" => "false","message" => "Error occured, please try again!") );
           }
       }
               mysqli_close($con);
    }
    } else{
           echo json_encode(array( "status" => "false","message" => "Error occured, please try again!") );
   }

?>

配置如下

<?php
$host="localhost";
$user="your username";
$password="your password";
$db = "your db name";

$con = mysqli_connect($host,$user,$password,$db);

// Check connection
if (mysqli_connect_errno())
 {
 echo "Failed to connect to MySQL: " . mysqli_connect_error();
 }else{  //echo "Connect"; 


  }

?>

引用自：https://serverfault.com/questions/918833