Monit：ping 一個網站 url 然後重啟應用伺服器

我正在使用這個配置來監控 apache2（ubuntu）：

/etc/monit/conf.d/apache2:

check process apache with pidfile /var/run/apache2/apache2.pid

   start program = "/etc/init.d/apache2 start" with timeout 60 seconds
   stop program  = "/etc/init.d/apache2 stop"

   alert f.bozzo@3-w.it with mail-format {
           from: monit@3-w.it
           subject: monit alert: $SERVICE $EVENT $DATE
           message: $DESCRIPTION
   }

   if failed port 80 protocol HTTP
           request /
           with timeout 7 seconds
           then restart

訪問 ‘request /’ 會導致 ubuntu-apache 預設頁面：如果您可以訪問它，那麼 Apache 正在工作。沒關係。

現在我也需要監控我的應用伺服器。所以我有第二個配置文件：

check process lucee with pidfile /opt/lucee/tomcat/work/tomcat.pid

       start program = "/etc/init.d/lucee_ctl start" with timeout 60 seconds
       stop program  = "/etc/init.d/lucee_ctl stop"

我不知道如何告訴 monit 請求完全限定的 URI，我需要類似的東西

if failed port 80 protocol HTTP
           request http://www.xxxxxx123123.com/
           with timeout 7 seconds
           then restart

但那說

/etc/monit/conf.d/lucee:13：錯誤：語法錯誤’

在重新載入。任何的想法？

基於樣本

 if failed host localhost port 80 with protocol http and request "/server-status" with timeout 25 seconds for 4 times within 5 cycles then restart

試著把

 if failed host www.xxxxxx123123.com port 80 with protocol http 
     and request "/" 
     with timeout 7 seconds 
     then restart

引用自：https://serverfault.com/questions/801763