Linux
為腳本日誌條目添加時間戳
目前我有我的 bash 腳本
exec 22>&2 21>&1 1>$log 2>&1
用於將 stderr 和 stdout 寫入日誌文件。我想為每個條目添加一個時間戳,但我還沒有找到一種簡單的方法來做到這一點。理想情況下,這將是對目前命令的簡單更改,將時間寫在其餘命令之前的同一行上。這是我在其中使用命令的腳本:
#!/bin/bash #This script takes the server to rysnc as an argument. You can also tell #the script to check the server_status.txt file. # #Example: /path/to/script/sync.sh grail true # #The arguments are order senstive. The server name must come before the status #check value. #Logfile LOG=/var/log/sync.log DIRECTORYS="auth/ keys/ log/mailwhen/ intranet/ www/calmaa/data/ www/admatch/data/ www/sfhsa/data/ www/hfa3_org www/padmatch/ www/serverdown/" if [ "x$2" == "xfalse" ]; then return 0 elif [ "x$2" == "xtrue" ]; then if [ `cat /srv/www/wan*/server_status.txt` == "primary" ]; then exit 0 fi else echo "Please use \"true\" or \"false\" for the second value." exit 1 fi # Copy stdout and stderr, and then open the logfile exec 22>&2 21>&1 1>$log 2>&1 # Here is how to restore stdout and stderr: # exec 2>&22 1>&21 for DIRECTORY in $DIRECTORYS; do rsync -azu --delete --bwlimit=500 $1:/srv/$DIRECTORY /srv/$DIRECTORY done
如果沒有看到更多您的腳本,我無法告訴您滿足您特定需求的最佳方式。但是,這是一種可以根據您的需要進行調整的通用方式。
exec > >(while read -r line; do printf '%s %s\n' "$(date --rfc-3339=seconds)" "$line"; done)
輸出的每一行文本都將附加其發生時間的時間戳。輸出將如下所示:
2013-09-04 21:32:14-05:00 An event occurred and this is the message 2013-09-04 21:32:37-05:00 Some time passed, another event produced a message