配置問題：PHP 在 CentOS 5.3 上通過 mod_fcgid

我已經在Google上搜尋並研究了很長一段時間，但只找到了一個詳盡的指南……那行不通。

我想在-上執行PHPmod_fcgid 。Apache2``CentOS 5.3

使用我目前的配置，我可以500 Internal Server Error使用.php-files。你能幫我弄清楚為什麼嗎？:)

httpd.conf：

<Directory "/var/www/html/">
   Options Indexes ExecCGI
   AllowOverride None
   Allow from all

   AddHandler fcgid-script .php
   FCGIWrapper /var/www/cgi-bin/php5/php-fcgi-starter .php
</Directory>

/var/www/cgi-bin/php5/php-fcgi-starter:

#!/bin/sh
PHPRC=/etc/
export PHPRC
export PHP_FCGI_MAX_REQUESTS=5000
export PHP_FCGI_CHILDREN=8
exec /usr/bin/php-cgi

php-cgi -v:

PHP 5.2.6 (cgi-fcgi) (built: May  2 2008 16:01:17)
Copyright (c) 1997-2008 The PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2008 Zend Technologies
   with the ionCube PHP Loader v3.1.29, Copyright (c) 2002-2007, by ionCube Ltd.

SeLinux關閉。

**編輯：**日誌…

[Mon Nov 02 05:17:49 2009] [notice] Apache/2.2.3 (CentOS) configured -- resuming normal operations
[Mon Nov 02 05:17:53 2009] [error] Not even headers for me :(
[Mon Nov 02 05:17:54 2009] [notice] mod_fcgid: call /var/www/html/phpinfo.php with wrapper /var/www/cgi-bin/php5/php-fcgi-starter
[Mon Nov 02 05:17:54 2009] [notice] mod_fcgid: server /var/www/html/phpinfo.php(13917) started
[Mon Nov 02 05:17:57 2009] [notice] mod_fcgid: process /var/www/html/phpinfo.php(13917) exit(communication error), terminated by calling exit(), return code: 120

SuExec_log：

[2009-11-02 04:55:27]: uid: (10001/www) gid: (2524/2524) cmd: php5
[2009-11-02 04:55:27]: target uid/gid (10001/2524 or 2523) mismatch with directory (10001/2523) or program (0/0)
[2009-11-02 04:57:19]: uid: (10001/www) gid: (2524/2524) cmd: php-fcgi-starter
[2009-11-02 04:57:19]: target uid/gid (10001/2524 or 2523) mismatch with directory (0/0) or program (0/0)

謝謝 ：）

SUExec 要求目錄 ( /var/www/html/) 和二進製文件 ( /var/www/cgi-bin/php5/php-fcgi-starter) 屬於同一使用者/組。看起來10001/2523擁有該目錄，而 root 擁有 php-fcgi-starter。修復它，或關閉 SUExec。

引用自：https://serverfault.com/questions/80516